Question

2x+3y=9,3x+4y=5 solve by elimination method

Answer 1

Answer:

$2x+3y=9 \ and \ 3x+4y=5$ will intersect at x = (-21)  and y = 17

Step-by-step explanation:

Given the equation of polynomial are

$2x+3y=9.............................(1)\\3x+4y=5.............................(2)$

Select the variable you want to eliminate, let us choose x.

Multiply or divide both the equation by non zero number to make the coefficient of x same.

Multiplying the equation 1 by 3

Multiplying the equation 2 by 2

Therefore,

$6x+9y=27....................(3)\\6x+8y=10.....................(4)$

Subtract equation 4 from equation 3, we get

$y=17$

Substitute the value of y in equation 1.

Therefore,

$2x+3(17)=9\\2x=9-51\\x=\frac{-42}{2}\\x=-21$

Therefore, the value of x is -21 and y is 17.

Answer 2

Answer:

x=-21,y=17

Step-by-step explanation:

2x+3y=9_______1

3x+4y=5_______2

multiply 2x+3y=9 by 3

multiply 3x+4y=5 by 2

6x+9y=27

6x+8y=10

eliminate 6x

y=17 put in equation 1

2x+3(17)=9

2x=(-42)

x=(-42)/2

x=(-21),y=17