Question

2x+3y=9
3x+4y=5
Solve equation by substituting method

Answer 1

Answer:

x= –21

y= 17

Step-by-step explanation:

2x+3y=9

y = 9-2x/3 _____(1) substitute in 3x+4y=5

3x + 4 ( 9-2x/3 )=5

(9x + 36-8x)/3 =5

x+36=15

x=15-36

x= ‐21 ____(2) substitute in (1)

y= 9‐2(-21) /3

y = 9+42/3

y = 51/3

y = 17

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Answer 2

Step-by-step explanation:

Solution :

The given equation are

2x + 3y = 9 ....(i)

3x + 4y = 5 ....(ii)

From equation (ii), we get

4y = 5 – 3x

=> y = 5 – 3x/4

Substituating this value of y in equation (i), we get

2x + 3y = 9

=> 2x + 3(5 – 3x/4) = 9

=> 2x + (15 – 9x/4) = 9

=> 8x + 15 – 9x/4 = 9

=> 8x – 9x + 15 = 36

=> –x = 36 – 15

=> –x = 21

=> x = 21/–1

=> x = –21.

Substituating this value of x in equation (ii), we get

3x + 4y = 5

=> 3(–21) + 4y = 5

=> –63 + 4y = 5

=> 4y = 5 + 63

=> 4y = 68

=> y = 68/4

=> y = 17.

Hence :

The solution is x = –21 and y = 17.