2x+3y=9
3x+4y=5
Solve it by substitution method
Answers
Answered by
4
2x+3y=9
3y=9-2x
y=(9-2x)/3
substitute in 3x+4y=5
3x+4(9-2x)/3 = 5
9x + 36 -8x =15
x + 36 =15
x= -21
y=(9-2x)/3
y = 3 - 2x/3
y = 3 - 2×(-21) /3
y=3+ 14
y=17
Answered by
2
Answer:
x=-21 and y=17
Step-by-step explanation:
2x+3y=9 ............(i)
3x+4y=5..............(ii)
substitute equation (i) into (ii)
2x+3y=9,
2x=9-3y
x=9-3y/2........(iii)
3(9-3y/2)+4y=5
27-9y/2 +4y/1
27-9y/2+ 4y/1=27-9y +8y/2
27-y/2=5
27-y=10
-y=-17
y=17
from .......(iii)
x=9-3y/2
but y=17, so
x=9-3x17/2
x=9-51/2
x=-42/2=-21
x= -21
ans, y=17 and x=-21
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