2x+3y=9 3x+4y=5 subsitute
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2x + 3y = 9 ... (i)
3x + 4y = 5 ... (ii)
from (i) eq.
2x + 3y = 9
2x = 9 - 3y
x = 9 - 3y/2
putting x value in equation (ii)
3x + 4y = 5
3( 9 - 3y/2) + 4y = 5
27 - 9y/2 + 4y = 5
27 - 9y + 8y/2 = 5
27 - y = 10
- y = 10 - 27
- y = - 17
y = 17.
now putting y value in equation (i)
2x + 3y = 9
2x + 3 × 17 = 9
2x + 51 = 9
2x = 9 - 51
2x = 42
x = 42/2
x = 21.
so , value of x = 21 and y = 17.
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