Question

2x+3y=9,3x+4y=5 substitution method

Answer 1

$2x + 3y = 9 \\ 2x = 9 - 3y \\ x = \frac{9 - 3y}{2} \\ 3x + 4y = 5 \\ 3( \frac{9 - 3y}{2} ) + 4y = 5 \\ 27 - 9y + 8y = 10 \\ - y = 10 - 27 \\ y = 17 \\ 2x + 3(17) = 9 \\ 2x = 9 - 51 \\ 2x = - 42 \\ x = - 21$

Answer 2

⇔⇔⇔⇔⇔ YOUR ANSWER ↓↓↓↓↓↓.

GIVEN :- 2x +3y = 9       ---------------------- 1
               3x +4y = 5       ----------------------  2 

To Find :- Value of x 

SOLUTION :- 
             Let us get a value of x by transposing,
             2x + 3y = 9
             x = $\frac{9-3y}{2}$
then, 
           putting value of x in second equation;
           3x + 4y = 5 

           $3 \frac{9-3y}{2}$ + 4y = 5 

          $\frac{27}{2} - \frac{9y}{2} + 4y = 5$

          $\frac{-9y}{2} + 4y = 5 - \frac{27}{2}$

           $\frac{-9y + 8y }{2} = \frac{10-27}{2}$

           $\frac{-y}{2} = \frac{-17}{2}$

          - 2y = -34 

            y = 17 
             Putting value in EQUATION
           x =    $\frac{9-3*17}{2}$

           x =    $\frac{-42}{2}$

          x = -21 

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