'2x-3y=-9'
a) rearrange equation so that it is in the form y= mx +c
b) find the gradient and y intercept of given line
c) sketch the graph for the given equation
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(a)y = mx + c Subtract c from both sides: y - c = mx Divide both sides by m: (y - c)/m = x And there's x!
The general equation of line in slope-intercept form is given by y=mx+c, where m is slope and c is y-intercept.
Compare equation (1) with general equation of line, we get
m=3 and c=−5
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