Math, asked by aashi59, 1 year ago

2x+3y=9 and 4x-6y=18 solve using substitution methad

Answers

Answered by enggmonika
23

Given: 2x+3y=9

           4x-6y=18

To Find: solve these equations by using substitution method.

Solution:

In substitution method, we solve one equation for one of the variables and substitute that value in other equation. after this step, there will be one equation only with one variable, which can be easily solved.

Step 1:

           2x+3y=9 ..............(eqn 1)

           4x-6y=18  ............(eqn 2)

divide equation 2 by 2 on both sides, we get:

           2x - 3y = 9

           2x = 9 + 3y

             x = (9+ 3y)/2   ..........(eqn 3)

step 2:

now put the value of x (from equation 3) in equation 1, we get:

            2((9+ 3y)/2) + 3y = 9

             (9 + 3y) +3y = 9

              9 + 6y =9

              6y = 9-9

              6y = 0

                y = 0   .........................(eqn 4)

step 3:

Now put the value of y = 0 (from equation 4) in equation 3, we get

           x = (9+ 3(0))/2

           x = 9/2

           x = 4.5  .......................(eqn 5)

so the answer is  x = 4.5 and y = 0.

step 4:

Verification:

to verify the answer we can put these values of x and y in any one of the equation 1 or equation 2.

put  x = 4.5 and y = 0  in equation 1, we get

             2x+3y=9

             2(4.5) + 3(0) = 9

              9 + 0 = 9

                9 = 9

            L.H.S. = R.H.S.

It means our answer is right.

           

Answered by hukam0685
24

Step-by-step explanation:

Given that: 2x+3y=9 and 4x-6y=18

To find: Solution of equations using substitution method

Solution:

In this method find value of one variable from one equation and place to other

2x + 3y = 9 \:  \: ...eq1 \\  \\ 3y = 9 - 2x \:  \:  \: ...eq2 \\  \\ 4x - 6y = 18 \:  \:  \: eq3 \\  \\

Value of y from eq 2 placed in eq3

4x - 2(3y) = 18 \\  \\ 4x - 2(9 - 2x) = 18 \\  \\ 4x + 4x - 18 = 18 \\  \\ 8x = 36 \\  \\ x =  \frac{36}{8}  \\  \\  \bold{x =  \frac{9}{2} } \\  \\

Now place the value of x in eq1

2x + 3y = 9 \\  \\ 2 \times  \frac{9}{2}  + 3y = 9 \\  \\ 3y = 9 - 9 \\  \\ 3y = 0 \\  \\  \bold{y = 0} \\

Thus,

\bold{x =  \frac{9}{2}=4.5,\:\: y = 0}\\

is the solution of given equations.

Hope it helps you.

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