Question

2x+3y=93x+9y=11 find value x and y

Answer 1

the value of x is ..........

Answer 2

$2x + 3y = 11..................(1) \\ 93x + 9y = 11.................(2) \\ (1) \times 3 - (2) \\ (6x + 9y = 33) - (93x + 9y = 11) \\ - 87x = 22 \\ x = \frac{ - 22}{87} \\ 3y = 11 - 2x \\ 3y = 11 -2 ( \frac{ - 22}{87} ) = 11 + \frac{44}{87} = \frac{957 + 44}{87} \\ 3y = \frac{1001}{87} \\ y = \frac{1001}{87 \times 3} = \frac{1001}{261}$