Question

(2x-3y) whole cube + (3y-4z) whole cube + ( 4z-2x) whole cube

Answer 1

Answer:3(2x-3y) (3y-4z) ( 4z-2x)

Step-by-step explanation:

(2x-3y)^3 + (3y-4z)^3+ ( 4z-2x)^3

Here, a= 2x-3y, b= 3y-4z, c= 4z-2x

Here, a+b+c= 2x-3y + 3y-4z + 4z-2x =0

Then, a^3+b^3+c^3= 3abc

(2x-3y)^3 + (3y-4z)^3+ ( 4z-2x)^3=

= 3(2x-3y) (3y-4z) ( 4z-2x)

Answer 2

Answer:

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