Question

2x+3y
x=2 y=3
find fast

Answer 1

Answer:

ANSWER

Let us Solve the equations 2x−3y=1 and x+2y=−3 by the method of elimination

2x−3y=1 ......(1)

x+2y=−3 ......(2)

Multiply eqn(1) by 1 and eqn(2) by 2

2x−3y=1 ......(3)

2x+4y=−6 ......(4)

Equation (3)−(4)

2x−3y−2x−4y=1−(−6)

⇒−7y=1+6=7

∴y=

−7

7

=−1

Substituting the value of y=−1 in eqn(1) we get

2x−3×−1=1

or 2x+3=1 or 2x=1−3=−2 or x=

2

−2

=−1

Hence the co-ordinates are (−1,−1) lies in third quadrant.

Step-by-step explanation:

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