Math, asked by abhinavraj7319864834, 20 days ago

(2x + 3y + z)^2 - (2x - 3y - z) ^ 2​

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Answers

Answered by kiranbhanot639
1

Answer:

(2x + 3y + z) { }^{2}  - (2x - 3y - z) {}^{2} .  \\ (4x + 9y + z  {}^{2} ) - (4x - 9y - z {}^{2} ). \\  = 4x {}^{2}  + 9y {}^{2}  + z { }^{2}  + 12xyz \\  + 4x {}^{2}  + 9y {}^{2}  + z {}^{2}  + 12xyz \\   = 8x {}^{2}  + 18y {}^{2}  + z {}^{2}  + 24xyz.

Answered by nihasrajgone2005
0

Answer:

(2x+3y+z)

2

−(2x−3y−z)

2

.

(4x+9y+z

2

)−(4x−9y−z

2

).

=4x

2

+9y

2

+z

2

+12xyz

+4x

2

+9y

2

+z

2

+12xyz

=8x

2

+18y

2

+z

2

+24xyz.

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