(2x+3y+z)² mathematics question emergency please answer fast
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Step-by-step explanation:
(2x)^2+(3y)^2+(z)^2+2(2x)(3y)+2(3y)(z)+2(z)(2x)
4x^2+9y^2+z^2+12xy+6yz+4xz
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(a-b-cº= a + b + c + 2ab-2bc-2ca
( 2x+3y-z) = (2x)* + (3y) (-2) -2 2x' 3y 2 3y'z-2 z 2x
=4x +9y-z*+ 12xy -6yz 4xz
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