Question

2x+3y+z=55,x-y=4 and y-x+z=12 then what are the values of x,y and z???

Answer 1

Answer:

Step-by-step explanation:2x+3y+z=55_______(1)

x-y=4______(2)

=> x=4+y______(3)

or y-x=-4_____(4)

y-x+z=12

=>-4+z=12

=>z=16

putting the value of z and x at equation no.(1)___

2(4+y)+3y+16=55

=>8+2y+3y=39

=>5y=31

=>y=(31/5)

putting the value of y at equation no.(3)______

x=4+(31/5)

=>x=(51/5)

so the values of x,y, and z are 51/5,31/5 & 16 in order.