Question

2x+ 3y-z=9
X+y+z=9
3x-y-z=1
Solve the above using cramers rule

Answer 1

Answer:

solution:-

Δ=∣∣∣∣∣∣∣∣

211−11−1311

∣∣∣∣∣∣∣∣

=2(1+1)−(−1)(1−1)+3(−2)=4−6=−2

Now, Δx=∣∣∣∣∣∣∣∣

962−11−1311

∣∣∣∣∣∣∣∣

=14Δy=∣∣∣∣∣∣∣∣

211962311∣∣∣∣∣∣∣∣

=−2Δz=

Answer 2

hope this doesn't helps you

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