Question

(2x-3y+z) the whole square​

Answer 1

Answer:

$= (2x - 3y + z)^{2} \\ we \: have \: to \: use \: the \: formule \\ ( {a} - {b} + {c} )^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2ac + 2ac \\ \\ here \: \: a = 2x \: \\ b = 3y \\ c = z \\ = (2x)^{2} + (3y)^{2} + {z}^{2} - 2(2x)(3y) - 2(3y)(z) + 2(2x)(z) \\ = 4 {x}^{2} + {9y}^{2} + {z}^{2} - 12xy - 6yz + 4xz \\ this \: is \: the \: correct \: answer....... \\ hope \: it \: helps.....$