Question

(2x - 4)^2 +( 4x - 2 )^2

Answer 1

(2x-4)^2+(4x-2)^2
=4x^2+16-16x +16x^2+4-16x
=20x^2+20-32x

Answer 2

$= > {(2x- 4)}^{2} + {(4x - 2)}^{2} \\ \\ = > {(2x)}^{2} + {(4)}^{2} - 2(2x)(4) + {(4x)}^{2} + {(2)}^{2} - 2(4x)(2) \\ \\ = > 4 {x}^{2} + 16 - 16x + 16 {x}^{2} + 4 - 16x \\ \\ = > 20 {x}^{2} - 32x + 20 \\ \\ = > 4(5 {x}^{2} - 8x + 5)$