2x^4+3x^3+2kx^2+3x+6 when x= -2 . find the value of K
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abhi sahi hai dekhna aaya ans correct
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sujata765:
x = -2
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2 (-2)^4 + 3 (-2)^3 + 2 K (-2 )^2 + 3 (-2) +6 =0
2 × 16 + 3 × (-8) + 4 k -6 +6 = 0
32 -24 +4k = 0
8 +4k = 0
4k = -8
k = -2
2 × 16 + 3 × (-8) + 4 k -6 +6 = 0
32 -24 +4k = 0
8 +4k = 0
4k = -8
k = -2
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