Question

(2x+4) एवं (x-1) अंश माप के कोण रेखिक कौण युगम हे ,ज्ञात कीजिए

Answer 1

Given

suppose

length = 2x + 4

breadth =X - 1

length * breadth= 0

According to question

(2x + 4 )(X - 1)= 0

2x^2 +2x - 4 = 0

x^2 + X - 2 = 0

(x + 1/2)^2 - (sqrt9/4)^2 = 0

(X + 1/2 + 3/2)(X + 1/2 - 3/2)=0

x = - 2and + 1

Answer 2

Answer:

LENGTH =2x+4

BREADTH=x-1

2x+4=0

x=-2

x-1=0

x=1

Step-by-step explanation:

AREA=L*B=(2x+4)(x-1)

$area = 2x {}^{2} - 2x + 4x - 4 \\ area = 2x {}^{2} + 2x - 4$

IF x, =1

AREA =2+2-4=0

THIS IS NOT POSSIBLE

THEREFORE x=-2

8+4-4=8

AREA=8

PERIMETER=2(L+B)

PERIMETER=2(2x+4+x-1) =2(3x-3)

PERIMETER=6x-6=6*2-6=12-6=6