Question

2x^4-x^3-11x^2+5x+5 if two zeros are √5×−√5 find other zeros

Answer 1

Step-by-step explanation:

-1/2 and 1 are the other two zeroes

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Answer 2

2x^4-x^3-11x^2+5x+5, if two zeros are √5 * -√5. Other two zeros are (1), (-1/2). Step wise explanation is given below:

- It is given that the two zeros are √5 * -√5.

Let p(x)=2x^4-x^3-11x^2+5x+5

- Since x=√5 is a zero, x-√5 is a factor

and x=-√5 is a zero, x+√5 is a factor

- Hence (x+√5) (x-√5) is a factor

=[(x)^2-(√5)^2]

=(x^2-

- Now by dividing the given polynomial p(x) by (x^2-5)

- Now by using splitting the middle term. We get,

=2x^2-x-1

=2x^2 - 2x + 1x - 1

=(2x+1) • (x-1)

- Solving a Single Variable Equation :

Solve : x-1 = 0

x = 1

- Solving a Single Variable Equation :

Solve : 2x+1 = 0

2x = -1

x=-1/2

- The division is solved below.

- So, other two zeros are (1), (-1/2).