2x+4y=6
5x-2y=3
Class 10 solve by elimination, substitution and cross multiplication method
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Step-by-step explanation:
2x+4y=6................(1)
5x-2y=3.................(2)
now from equation 1
2x+3y=6
or 2x=6-3y
so x=6-3y/2...............3
now put the value of x in eq. 2
5(6-3y/2)-2y=3
or 30-15y/2-2y=3
or 30-15y-4y/2=3
or30-15y-4y=6
or. -19y=6-30
or-19y=-24
so y=25/19
from eq 3
x=6-3(25/19)/2
or x=6-75/19/2
=6-150/19=144-150/19=-6/19
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