Question

2x+4y=6 and 3x+5y=8
solve elimination method​

Answer 1

Answer:

x=1 and y=1

Step-by-step explanation:

(equ1)*3 ===>  6x+12y=18

(equ2)*2 ===>  6x+10y=16

Subtract above equ

2y=2   ==>   y=1

2x+4(1)=6

2x=6-4

2x=2

x=1

Answer 2

Answer:

2x + 4y = 6 multiply by 3 in equation 1

3x + 5y = 8 multiply by 2in equation 2

now you get

6x + 12y = 18 eq 3

6x + 10y = 16 now change sign (eq 4)

(-) (-) (-)

now u get equation

2y = 2

y = 1

put value of y in eq 1

2x +4 × 1 = 6

2x + 4 =6

2x =6 – 4

2x = 2

x = 1

value of x and y by elimination method

x = 1 , y = 1