Question

2x+4z=2y+28
X+11y=5z-41
3x-3=2y+z

Answer 1

Answer:

x= 20/11

z= 59/11

y= -16/11

Step-by-step explanation:

2x+4z=2y+28

x+11y=5z−41

3x−3=2y+z

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Reorder the equations.

x+11y=5z−41

2x+4z=2y+28

3x−3=2y+z

Solve x+11y=5z−41 for x.

x=−11y+5z−41

Substitute −11y+5z−41 for x in the second and third equation.

2(−11y+5z−41)+4z=2y+28

3(−11y+5z−41)−3=2y+z

Solve these equations for z and y respectively.

z=  55/7  + 12/7y

y = -18/5 + 2/5z

Substitute z  55/7  +  12/7  for z in the equation y=−18/5 +2/5z

y = -18/5 + 2/5( 55/7  + 12/7y) = -16/11

Substitute −16/11 for y in the z equation

z= 55/7 + 12/7(-16/11) = 59/11

Substitute -16/11 for y and 59/11 for z in x equation

x= −11(-16/11)+5(59/11)−41= 20/11