Question

(2x + 5)^2 algebraic identites solve​

Answer 1

$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION\: \: \red {\mid}}}}}}}} \:$

$\bf{ \sf{ \: \: \: (2x + 5) {}^{2} }} \\ \\ \bf{ \sf{ = (2x) {}^{2} + 2 \times (2x) \times (5) + (5) {}^{2} }} \\ \\ \bf{ \sf{ = \underline{ \: \: \red{4x {}^{2} + 20x + 25 } \: \: }}}$

$\underline{ \underline{ \rm{\pink{ \: \: \: IDENTITY \: \: \: \: USED \: \: \: }}}}$

$\boxed{ \boxed{\bf{ \red{(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2} }}}}$

$\huge{ \underline{ \underline{ \bf{ \sf{ \red{ \: \:OR \: \: }}}}}}$

$\rm{(2x + 5) {}^{2} } \\ \\ \rm{ = (2x + 5)(2x + 5)} \\ \\ \rm{ = 2x(2x + 5) + 5(2x + 5)} \\ \\ \rm{ = 4x {}^{2} + 10x + 10x + 25 } \\ \\ \rm{ = \underline { \red{ \: \: 4x {}^{2} + 20x + 25 \: \: }}}$

Answer 2

Answer:-

$\begin{lgathered}\bf{ \sf{ \: \: \: (2x + 5) {}^{2} }} \\ \\ \bf{ \sf{ = (2x) {}^{2} + 2 \times (2x) \times (5) + (5) {}^{2} }} \\ \\ \bf{ \sf{ = \underline{ \: \: \red{4x {}^{2} + 20x + 25 } \: \: }}}\end{lgathered}$

OR

$\begin{lgathered}\rm{(2x + 5) {}^{2} } \\ \\ \rm{ = (2x + 5)(2x + 5)} \\ \\ \rm{ = 2x(2x + 5) + 5(2x + 5)} \\ \\ \rm{ = 4x {}^{2} + 10x + 10x + 25 } \\ \\ \rm{ = \underline { \red{ \: \: 4x {}^{2} + 20x + 25 \: \: }}}\end{lgathered}$