Question

2x – 5, 3x + 1 and 5x are terms of AP. Find x.​

Answer 1

Answer:

2x,x+8,3x+1 are in A.P.

Thus,

(x+8)−2x=(3x+1)−(x+8)

8−x=2x−7

3x=15

x=5

Answer 2

Answer:

7

Step-by-step explanation:

Given:-

Arithmetic Progression (AP) $=2x-5, 3x+5, 5x$

To find:-

$x$

Solution:-

Common Difference $(d)=a_{2}-a$

$d=3x+1-(2x-5)$

$d=3x+1-2x+5$

$d=x+6$

$d=a_{3}-a_{2}$

$d=5x-(3x+1)$

$d=5x-3x-1$

$d=2x-1$

Using Euclid's Theorem (Things which are equal to the same thing, are equal to one another),

$x+6=2x-1$

$2x-x=6+1$

$x=7$

∴ The value of $x$ is 7