2x^5-5x^4-12x^3+23x^2+16x-12 Factorizar usando division sintetica
Answers
Answered by
1
Answer:
(x + 1)(x + 2)(x - 2)(x - 3)(2x - 1)
Step-by-step explanation:
(- 1) is zero of given polynomial.
Let (2 - 5
- 12
+ 23x² + 16x - 12 )÷ (x + 1) =
(2 - 7
- 5
+ 28x - 12)
2 is another zero of given polynomial.
(2 - 7
- 5
+ 28x - 12) ÷ (x - 2) =
(2 - 3
- 11x + 6)
(-2) is another zero of given polynomial.
(2 - 3
- 11x + 6) ÷ (x + 2) =
(2x² - 7x + 3) ;
(2x² - 7x + 3) = (x - 3)(2x - 1)
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Answered by
5
So tge zeroes of the polynomial is -1,2,-2,3,1/2.
this is find by the help of trial and error method .
Full explanation is in the given attachment
HOPE IT IS HELPFUL
⚘#thank you#⚘
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