Math, asked by pemar, 7 months ago

2x^5-5x^4-12x^3+23x^2+16x-12 Factorizar usando division sintetica

Answers

Answered by Anonymous
1

Answer:

(x + 1)(x + 2)(x - 2)(x - 3)(2x - 1)

Step-by-step explanation:

(- 1) is zero of given polynomial.

Let (2x^{5} - 5x^{4} - 12x^{3} + 23x² + 16x - 12 )÷ (x + 1) =

(2x^{4} - 7x^{3} - 5x^{2} + 28x - 12)

2 is another zero of given polynomial.

(2x^{4} - 7x^{3} - 5x^{2} + 28x - 12) ÷ (x - 2) =

(2x^{3} - 3x^{2} - 11x + 6)

(-2)  is another zero of given polynomial.

(2x^{3} - 3x^{2} - 11x + 6) ÷ (x + 2) =

(2x² - 7x + 3) ;

(2x² - 7x + 3) = (x - 3)(2x - 1)

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Answered by surendrasahoo
5

So tge zeroes of the polynomial is -1,2,-2,3,1/2.

this is find by the help of trial and error method .

Full explanation is in the given attachment

HOPE IT IS HELPFUL

#thank you#

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