2x–5{7–(x–6)+3x}–28=39
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Answered by
16
2x-5(7-x+6-3x)=39+28
2x-5(7-x+6-3x)=67
2x-5(13-4x)=67
26x-8x-26+20x=67
38x-26=67
38x=67+26
38x=93
x=93/38
x=2.44
2x-5(7-x+6-3x)=67
2x-5(13-4x)=67
26x-8x-26+20x=67
38x-26=67
38x=67+26
38x=93
x=93/38
x=2.44
Satan2002:
wrong
Answered by
4
2x-5{7-x+6+3x}-28=39
2x-5{13+2x}=39+28
(2x-5)(13+2x)= 67
2x(13+2x)-5(13+2x)=67
26x+4x^2-65-10x=67
4x^2-10x+26x-65-67=0
4x^2+16x-132=0
4(x^2+4x-33)=0
x^2+4x-33=0
The middle term break is not coming.
2x-5{13+2x}=39+28
(2x-5)(13+2x)= 67
2x(13+2x)-5(13+2x)=67
26x+4x^2-65-10x=67
4x^2-10x+26x-65-67=0
4x^2+16x-132=0
4(x^2+4x-33)=0
x^2+4x-33=0
The middle term break is not coming.
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