Question

(2x+5b)^2=?
And also
(202)^2=?

Answer 1

(2x+5b)^2 = 4x^2 + 25b^2 + 20xb

and 

(202)^2 = (200+2)^2 

(200+2)^2 = (200^2 + 2^2  +2(202)

(200+2)^2 = 40000+4 + 404

(200+2)^2 = 40004 + 404

(200+2)^2 = 40804

Answer 2

HERE is Your TWO SOLUTIONS.

There, (2x+5b)²
we use formula = (x+y)²= x²+y²+2ab
=> 2x²+5b²+2*2x*5b
=>4x²+25b²+20xb ans.



here , (202)²
we have, (202)²

=>(200+2)²=(200²+2²+2(202)

=>(200+2)² =40000+4+404

=>(200+2)²= 40804 ANSWER.