Question

2x+5x²+24x+7x²-8
solve it fast
please send the answer​

Answer 1

Answer:

Here's yor answer

Step-by-step explanation:

2x+5x²+24x+7x²-8

12x²+26x-8

24x^2-26x-8 =0.

2(12x^2 - 13x - 4)=0.

12x^2 - 13x - 4 = 0/2

12x^2 - 13x - 4 = 0.

Factoring  12x^2 - 13x - 4 =0.

The first term is,  12x2  its coefficient is  12 .

The middle term is,  -13x  its coefficient is  -13 .

The last term, "the constant", is  -4

Step-1 : Multiply the coefficient of the first term by the constant   12 • -4 = -48

Step-2 : Find two factors of  -48  whose sum equals the coefficient of the middle term, which is   -13 .

-16   +   3   =   -13   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -16  and  3

12x^2 - 16x + 3x - 4 =0.

=>4x(3x-4)1(3x-4)=0

=>(4x+1)(3x-4)=0.

=>4x+1=0 or 3x-4 =0.

=>4x= -1 or 3x=4.

=>x=-1/4 or x= 4/3.

24x^2-26x-8 => 2 • (3x - 4) • (4x + 1).

Hope you understand.