Question

2x+5y=1------1
x^2+5x-4y^2+10=0-----2

Do it in substitution Method

Answer 1

Step-by-step explanation:

2x+5y=1

x²+5x-4y²+10=0

5y=1-2x

y=1-2x/5

x²+5x-4y²+10=0

x²+5x-4(1-2x/5)+10=0

x²+5x+(-4+8x/5)+10=0

(ײ+25×-4+8×)/5=-10

ײ+33×-4=-50

ײ+33×=-46