Math, asked by mohsinn, 2 months ago

2x+5y=10
5X-3y=20
Solve for x and y

Answers

Answered by aayushsharma7956
2

Answer:

y = 5/3

x = 5

Step-by-step explanation:

EQUATIONS GIVEN,

2x+5y=10    (eq. 1)

5x-3y=20    (eq. 2)

SO,

IN EQUATION 2,

5x-3y=20

x = (20+3y)/5

NOW,

SUBSTITUTING IT INTO EQUATION 1,

WE GET,

2x+5y=10

2[(20+3y)/5] + 5y=10

(40+6y)/5 = 10

40+6y=10*5

40+6y = 50

6y = 50-40

6y = 10

y = 10/6

y = 5/3

SO,

x = (20+3y)/5

x = [20+3(5/3)]/5

x = 25/5

x = 5

SO,

y=5/3

x = 5

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                               !!!JAI SHREE KRISHNA!!!

Answered by karanthprabhakar
1

Answer:

Hey buddy!

x = 130/31 and y = 10/31

Step-by-step explanation:

see the pic tagged! Solved using both elemination and substitution methods ...

Since it's an unusual ans, I ask u to check the question once... nevertheless, if that is the question, then according to me ans is correct since both the methods gave same ans...

Hope this helps ya!

Gunnite❤️

Regards,

@Paavana karanth.

***

@Aayush Sharma, if ur still watching, in the step

2[(20+3y)÷5]+ 5y = 10, there's 5y and u have skipped it in next step...

Attachments:
Similar questions