Question

-2x+5y= -10 And 3x-9y =15 by substitution method

Answer 1

Given equations

$-2x+5y=-10\\\implies 2x-5y=10\\\implies 2x=10+5y\\\ \implies x = \dfrac{10+5y}{2}$

Substituting the value of x in the second equation, we get,

$\implies 3(\dfrac{10+5y}{2}) -9y=15$

$\implies \dfrac{30+15y}{2} -9y=15$

Multiplying the entire equation by 2, we get,

$\implies 30+15y-18y=30$

$\implies -3y=0$

$\implies y= 0$

Substituting the value of y in x we get,

$\implies x=5$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \ y \ are \ 5 \ and \ 0 \ respectively}}}}}$

                                                     

Answer 2

Step-by-step explanation:

$2(3x - 9y = 15)$

$3( - 2x + 5y = - 10)$

$6x - 18y = 30$

$- 6x+ 15y = - 30$

$y = 0$

$x = 5$