Question

2x-5y-16=0and3x+4y-1=0by subtitution method

Answer 1

2x-5y-16=0
3x+4y- 1=0

on dividing both we get 23x-69=0
23(x-3)=0
on putting 23 on left side it will go into
the denominator like x-3=0×1/23
x-3=0
x=3