Question

2x+5y=17,3x+7y=29 by elimination form

Answer 1

Answer:

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Answer 2

Given:-

Two polynomials 2x+5y = 17 and 3x+7y = 29

To find:-

value of x

Method:-

Elimination method

Solution:-

We have,

2x+5y = 17                                                                             -(1)

and, 3x+7y = 29                                                                     -(2)

Multiplying (1) by 3 and (2) by 2, we get,

6x+15y = 51                                                                             -(3)

and,  6x+14y = 58                                                                   -(4)

Subtracting (4) from (3), we get,

15y-14y = 51-58

∴ y = -7

Put y = -7 in (1), we get,

2x+5(-7) = 17

⇒2x-35 = 17

⇒2x = 17+35 = 52

⇒x = $\frac{52}{2}$ = 26

Hence, x = 26 and y = -7.