Question

2x+5y-19=0 , 5x-2y-4=0

Answer 1

Step-by-step explanation:

$2x + 5y - 19 = 0$

$2x + 5y = 19$

$2x = 19 - 5y$

$x = \frac{19 - 5y}{2}$

$substitute \: x = \frac{19 - 5y}{2}$

$in \: equation \: 2$

$5( \frac{19 - 5y}{2} ) - 2y - 4 = 0$

$\frac{95 - 25y}{2} - 2y = 4$

$\frac{95 - 25y - 4y}{2} = 4$

$\frac{95 - 29y}{2 } = 4$

$95 - 29y = 4 \times 2$

$95 - 9y = 8$

$- 9y = - 87$

$y = \frac{ - 87}{ - 9}$

$y = \frac{29}{3}$

$x = \frac{19 - 5y}{2}$

$x = 19 - 5( \frac{29}{3} )by \: 2$

$x = \frac{145}{3} by2$

$x = \frac{145}{6}$

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Answer 2

Answer:

x= 2

y= 3

Step-by-step explanation:

2x+5y-19=0       ...(1)

5x-2y-4=0         ...(2)

multiplying first by 2 and second by 5, we get

4x+10y=38

25x-10y=20

adding both , we get

29x=58

=>x=2

put value of x in (2), we get

10-2y-4=0

=>2y=6

=>y=3

HOPE IT HELPS,

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