Question

(2x-5y)^2+(3x-5y)^2​

Answer 1

Step-by-step explanation:

Given equations are

3x−5y+1=0

2x−y+3=0

Since, the system has unique solution at x=x1 and y=y1

That means the lines intersect at only one point (x1,y1)

By putting x=x1 and y=y1 in given equations

3x1−5y1+1=0     .....(1)

2x1−y1+3=0        .....(2)

From equation(2), we have 

y1=2x1+3      .....(3)

Putting the value of y1 in  equation(1)

3x1−5(2x1+3)+1=0

⇒3x1−10x1−15+1=0

⇒−7x1−14=0

⇒−7x1=14

⇒x1=−2

Put this value in equation (3), we get

y1=

Answer 2

Step-by-step explanation:

Hey mate is that ANSWER was wrong⊙﹏⊙

oh sorry mate sorry very sorry (˘･_･˘) where I did mistake (˘･_･˘)