(2x-5y)^2 = 4x^2 + 25y^2 - Kxy then K =
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(2x - 5y)^2
= (2x)^2 - 2.(2x).(5y) + (5y)^2
= 4x^2 - 20xy + 25y^2
compare this with the equation 4x^2 + 25y^2 - Kxy
we get the value of k = 20
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