(2x-5y)^2
solve it fast
Answers
Answer:
I think correct answer is (
2
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5
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2
(2x-5y)^{2}
(2x−5y)2
Simplify
1
Expand the square
(
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5
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2
\left(2x-5y\right)^{2}
(2x−5y)2
(
2
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5
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(
2
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5
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(2x-5y)(2x-5y)
(2x−5y)(2x−5y)
2
Distribute
(
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(
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{\color{#c92786}{(2x-5y)(2x-5y)}}
(2x−5y)(2x−5y)
2
(
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−
5
(
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{\color{#c92786}{2x(2x-5y)-5y(2x-5y)}}
2x(2x−5y)−5y(2x−5y)
3
Distribute
2
(
2
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−
5
(
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{\color{#c92786}{2x(2x-5y)}}-5y(2x-5y)
2x(2x−5y)−5y(2x−5y)
4
2
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1
0
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5
(
2
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{\color{#c92786}{4x^{2}-10xy}}-5y(2x-5y)
4x2−10xy−5y(2x−5y)
4
Distribute
4
2
−
1
0
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5
(
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4x^{2}-10xy{\color{#c92786}{-5y(2x-5y)}}
4x2−10xy−5y(2x−5y)
4
2
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1
0
−
1
0
+
2
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2
4x^{2}-10xy{\color{#c92786}{-10xy+25y^{2}}}
4x2−10xy−10xy+25y2
5
Combine like terms
4
2
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1
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2
4x^{2}{\color{#c92786}{-10xy}}{\color{#c92786}{-10xy}}+25y^{2}
4x2−10xy−10xy+25y2
4
2
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2
0
+
2
5
2
4x^{2}{\color{#c92786}{-20xy}}+25y^{2}
4x2−20xy+25y2
Answer:
(2x - 5y)*(2x - 5y) = 2x*2x -2x*5y -5y*2x -5y*-5y
= 4x2 -20xy + 25y2
Step-by-step explanation:
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