CBSE BOARD X, asked by ShivangKatyayan613, 10 months ago

2x + 5y = 20; 3x + 6y = 12.

Answers

Answered by 9565Ranaji
1

Answer:

hey mate

Explanation:

Let's isolate

x

in the first:

x

=

18

3

6

y

3

x

=

6

2

y

Now, we replace this found

x

in the second:

2

(

6

2

y

)

+

5

y

=

20

12

4

y

+

5

y

=

20

12

+

y

=

20

y

=

8

Now, you just replace this

y

=

8

in the isolated

x

above:

x

=

6

2

(

8

)

x

=

6

16

=

10

Answered by Arnav0308
3

Answer:

2x+5y=20,3x+6y=12

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x+5y=20,3x+6y=12

2x+5y=20,3x+6y=12

xx

2x+5y=20

2x+5y=20

5y

2x=-5y+20

2x=−5y+20

2

x=\frac{1}{2}\left(-5y+20\right)

x=

2

1

(−5y+20)

\frac{1}{2}=0.5

-5y+20

x=-\frac{5}{2}y+10

x=−

2

5

y+10

-\frac{5y}{2}+10

x3x+6y=12

3\left(-\frac{5}{2}y+10\right)+6y=12

3(−

2

5

y+10)+6y=12

3-\frac{5y}{2}+10

-\frac{15}{2}y+30+6y=12

2

15

y+30+6y=12

-\frac{15y}{2}

6y

-\frac{3}{2}y+30=12

2

3

y+30=12

30

-\frac{3}{2}y=-18

2

3

y=−18

-\frac{3}{2}=-1.5

y=12

y=12

12yx=-\frac{5}{2}y+10

x

x=-\frac{5}{2}\times 12+10

x=−

2

5

12+10

-\frac{5}{2}=-2.5

12

x=-30+10

x=−30+10

10-30

x=-20

x=−20

Explanation

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