Math, asked by Uditdon6666, 9 months ago

2x+5y+2y=6;5x-7y=-29;z=1
Solution :
{x,y,z} = {-23/7,88/49,1}

System of Linear Equations entered :
[1] 2x+5y+2y=6
[2] 5x-7y=-29
[3] z=1

Answers

Answered by renu51622
2

Answer:

2x+5y+2y=6;5x-7y=-29;z=1

Solution :

{x,y,z} = {-23/7,88/49,1}

System of Linear Equations entered :

[1] 2x+5y+2y=6

[2] 5x-7y=-29

[3] z=1

Equations Simplified or Rearranged :

[1] 2x + 7y = 6

[2] 5x - 7y = -29

[3] z = 1

Solve by Substitution :

// Solve equation [3] for the variable z

[3] z = 1

// Solve equation [2] for the variable x

[2] 5x = 7y - 29

[2] x = 7y/5 - 29/5

// Plug this in for variable x in equation [1]

[1] 2•(7y/5-29/5) + 7y = 6

[1] 49y/5 = 88/5

[1] 49y = 88

// Solve equation [1] for the variable y

[1] 49y = 88

[1] y = 88/49

// By now we know this much :

x = 7y/5-29/5

y = 88/49

z = 1

// Use the y value to solve for x

x = (7/5)(88/49)-29/5 = -23/7

Solution :

{x,y,z} = {-23/7,88/49,1}

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