Math, asked by gsaksham2090, 6 months ago

(2x-5y)^3 using suitable identity

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Answered by Anonymous
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 \huge\color{aqua}\implies\huge \bold \red{ Answer}

(2x - 5y) {}^{3}  \\ on \: using \: identity \\ (x - y) {}^{3}   =x {}^{3}  - y {}^{3}  - 3  x  y(x - y) \\  = 2x {}^{3}  - 5y {}^{3}  - 3 \times 2x \times 5y(2x - 5y) \\  = 2x {}^{3}  - 5y {}^{3}  - 30xy(2x - 5y) \\ =  2x {}^{3}  -  {5y}^{3}  - 60x {}^{2} y  + 150xy {}^{2}  \\

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