Question

2x+5y=7 3x+KY=5 find the value of k through unique solution​

Answer 1

Answer:

-10/3

Step-by-step explanation:

Let ,

the given system of linear equations are of the form

2x+ky=1     a₁x +b₁y+c₁ = 0                    

3x-5y=7     a₂x +b₂y+c₂ = 0

the condition for unique solution is a₁/a₂≠  b₁b₂

here ,

a₁ = 2, a₂ = 3

b₁ = k ,b₂ = -5

⇒ 2/3 ≠k/ -5

⇒-10 ≠ 3k

⇒k ≠ -10/3

therefore , the value of k is any real number other then -10/3

Answer 2

The answer is k not equal to 15/2