Question

2x-5y=a
bx+10y=-8
In the system of equations above, a and b are constants. if the system has infinitely many solutions,
What is the value of a?
Explain your answer step by step

Answer 1

Step-by-step explanation:

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Answer 2

Answer:2x-5y-a=0

             bx+10y+8=0

a1/a2=b1/b2=c1/c2

2/b=-5/10=-a/8

-5/10=-a/8

cross multiply

-40=-10a

a=-40/-10

a=4

now,

2/b=-5/10

cross multiply

20=-5b

b=20/-5

b=4

therefore, a=4,b=4

Step-by-step explanation: