2x+6y +11=0 6x + 20y-62+3=0 6y-18z+1=0
slove in inverse method
Answers
Answer:
So, the system is inconsistent. Alternate method: The given system of equations is equivalent to the single matrix equation: We shall reduce the coefficient matrix A to triangular form by E-row operations on it and apply the same operations on the right-hand side, i.e. on the matrix B. Performing R2 → R2 - 3R1, we have Performing R3 → R3 - 3R2, we have The last equation of this system is 0x + 0y + 0z = -91. This shows that the given system is not consistent.Read more on Sarthaks.com - https://www.sarthaks.com/544938/show-that-the-equations-2x-6y-11-0-6x-20y-6z-3-0-and-6y-18z-1-0-are-not-consistent
Step-by-step explanation:
Answer:
Correct option is C)
Given:
2x+6y+11=0
6x+20y−6z+3=0
6y−18z+1=0
Converting above equations in the determinant form, we get
Δ=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
6
20
6
0
−6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Here, Δ=−648+648=0
Now,
Δ
1
=
∣
∣
∣
∣
∣
∣
∣
∣
−11
−3
−1
6
20
6
0
−6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Δ
1
=3276
=0
Δ
2
=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
−11
−3
−1
0
6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Δ
2
=−1092
=0
And Δ
3
=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
6
20
6
−11
−3
−1
∣
∣
∣
∣
∣
∣
∣
∣
Δ
3
=−364
=0
So, here D=0 and no-one among D
1
,D
2
,D
3
is 0.
Hence, the system is inconsistent
Hence, option C