2x-6y=-6, 15x+6y=6 elimination process
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adding eq. (1) from (2) we get,
15x+6y+2x-6y=6-6
18x=0
x=0
putting x=0 in eq. 1 we get
2×0-6y=-6
0-6y=-6
-6y=-6
y=1
hence x=0and y=1
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