Math, asked by isk16240, 3 months ago

(2x+7)/5-(x-3)10+(x+1)/15=0

Answers

Answered by devarora999
2

Step-by-step explanation:

(2x+7)/5-(x-3)10+(x+1)/15=0

Taking LCM

(6x+21-2x+6+x+1)/15= 0

6x+21-2x+6+x+1 = 0

5x+28 = 0

x = -28/5

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Answered by spencer11
0

Answer:

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Step-by-step explanation:

(2x+7)/5 - (x-3)10 + (x+1)/15 = 0

(2x+7)/5 - 10x-30 + (x+1)/15 = 0

(2x+7)/5  + (x+1)/15 = 10x + 30

[3(2x+7) + (x+1)] / 15 = 10x + 30

6x + 21 + x + 1 = (10x+30)15

7x + 22 = 150x + 450

7x - 150x = 450 - 22

-143x = 428

Divide both sides by -143

-143x/-143 = 428/-143

x = -2(142/143)

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