Question

2x-(7-5x)/9x-(3+4x) = 7/6

Answer 1

2x-(7-5x)/9x(3+4x)=7/6
2x+5x -7/9x-4x-3=7/6
7x-7/5x-3=7/6
6(7x-7)=7(5x-3)
42x-42=35x-21
42x-35x=-21+42
7x=21
x=3

Answer 2

$\frac{2x - (7 - 5x) }{9x - (3 + 4x)} = \frac{7}{6} \\ \frac{2x - 7 + 5x}{9x - 3 - 4x} =\frac{7}{6} \\ \frac{7x - 7}{5x - 3} = \frac{7}{6} \\ 6(7x - 7) = 7(5x - 3) \\ 42x - 42 = 35x - 21 \\ 42x - 35x = -21 + 42 \\ 7x = 21 \\ x = \frac{21}{7} \\ x = 3$

Therefore the answer for this question is  3.