(2x/7-y/2)^2-(2x/7+y/2)^2
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We know that, a² - b² = (a + b) (a - b)
Here, LHS is given
a = (2x/7-y/2) and b = (2x/7+y/2)
So the answer is ( 2x/7-y/2 + 2x/7+y/2) ( 2x/7-y/2 - 2x/7- y/2)
After cancellation, we get (-2y/2)
HOPE THIS HELPS !!!
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