Math, asked by shashisaini6476, 12 hours ago

2x+7y=10
3x+y=6
Solve it by elemination method

Answers

Answered by misscutie94
3

Answer:

Solution :-

2x + 7y = 10 and 3x + y = 6 by elimination method.

2x + 7y = 10 . . . . . (1)

3x + y = 6 . . . . . . (2)

Multiply equation (1) by 3, (2) by 2, we get

6x + 21y = 30 . . . . . (3)

6x + 2y = 12 . . . . . . (4)

Adding (3) and (4) we get,

6x + 21y = 30

6x + 2y = 12

(-) (-) (-)

_____________

19y = 18

y = 18/19

Substituting the value of y = 18/19 in equation (1) we get,

2x + 7y = 10

➻ 2x + 7(18/19) = 10

➻ 2x + 126/19 = 10

➻ 2x = 10 - 126/19

➻ 2x = 190 - 126/19

➻ 2x = 64/19

➻ x = 64/19 × 1/2

➻ x = 32/19

The value of x = 32/19, y = 18/19 is the solution of the system of the given equations.

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