2x+7y=10
3x+y=6
Solve it by elemination method
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Solution :-
2x + 7y = 10 and 3x + y = 6 by elimination method.
2x + 7y = 10 . . . . . (1)
3x + y = 6 . . . . . . (2)
Multiply equation (1) by 3, (2) by 2, we get
6x + 21y = 30 . . . . . (3)
6x + 2y = 12 . . . . . . (4)
Adding (3) and (4) we get,
6x + 21y = 30
6x + 2y = 12
(-) (-) (-)
_____________
19y = 18
y = 18/19
Substituting the value of y = 18/19 in equation (1) we get,
2x + 7y = 10
➻ 2x + 7(18/19) = 10
➻ 2x + 126/19 = 10
➻ 2x = 10 - 126/19
➻ 2x = 190 - 126/19
➻ 2x = 64/19
➻ x = 64/19 × 1/2
➻ x = 32/19
∴ The value of x = 32/19, y = 18/19 is the solution of the system of the given equations.
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