Math, asked by Anonymous, 8 months ago

2x+7y=11 and 3x_y=5 solve by substitution method​

Answers

Answered by karhaan7374
6

Answer:

Step-by-step explanation:

2x+7y = 11

Therefore 2x = 11- 7y

x = (11-7y)/2  ---(i)

3x-y = 5 (given) ---(ii)

Substituting values of (i) in (ii) we get:

3*(11-7y)/2 - y = 5

(33-21y)/2 -2y/2 = 5

(33-19y)/2 = 5

(33-19y) = 10

19y= 23

y= 23/19

x= (11-7*23/19)*1/2

Answered by asopashiven
6

Answer: 2x + 7y=11

x=(11-7y)/2

3x-y=5

3[(11-7y)/2] - y= 5

(33-21y)/2-y=5

(33-21y-2y)/2=5

(33-19y)/2=5

33-19y=5*2

33-19y=10

-19y=10-33

-19y=-22

y=22/19

Step-by-step explanation:

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