2x+7y=11 and 3x_y=5 solve by substitution method
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Answered by
6
Answer:
Step-by-step explanation:
2x+7y = 11
Therefore 2x = 11- 7y
x = (11-7y)/2 ---(i)
3x-y = 5 (given) ---(ii)
Substituting values of (i) in (ii) we get:
3*(11-7y)/2 - y = 5
(33-21y)/2 -2y/2 = 5
(33-19y)/2 = 5
(33-19y) = 10
19y= 23
y= 23/19
x= (11-7*23/19)*1/2
Answered by
6
Answer: 2x + 7y=11
x=(11-7y)/2
3x-y=5
3[(11-7y)/2] - y= 5
(33-21y)/2-y=5
(33-21y-2y)/2=5
(33-19y)/2=5
33-19y=5*2
33-19y=10
-19y=10-33
-19y=-22
y=22/19
Step-by-step explanation:
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