Question

2x+7y=11, x-3y=5 are simultaneous linear pair of equations,to find the nature of linear equations ​

Answer 1

Answer:

The given system of equations is

2x+7y=11 .(i)

x−3y=5 .(ii)

Putting x=2,y=1 in equation (i), we have

LHS=2×2+7×1=11=RHsSo, x=2 and y=1 satisfy equation (i)

Putting x=2,y=1 in equation (i), we have

LHS =2×1−3×1=−1

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= RHS

So, x=2 and y=1 do not satisfy equation (ii)

Hence, x=2,y=1 is not a solution of the given system of equations.

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